? ×?×? =13728 difference=2 find three numbers
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Answered by
1
Answer:
\Large A = P \left(1+\frac{r}{100}\right)^{n} => 7986 = 6000 \left(1+\frac{10}{100}\right)^{n} \)
=> \( \Large \frac{7986}{6000}=\frac{11}{10}^{n} => \frac{1331}{1000}= \left(\frac{11}{10}\right)^{n} => n = 3 years \)
Answered by
0
Answer: 22, 24, 26
Step-by-step explanation:
Let x be the first number in this sequence.
Let's say x = 10
Then 10 x 12 x 14 = 1680. Way too small
Now let's say x = 20
Then 20 x 22 x 24 = 10560. Almost there
Now let's say x = 25
Then 25 x 27 x 29 = 19575. Too much
Now let's say x = 23
Then 23 x 25 x 27 = 15525. Almost there
Now let's say x = 22
Then 22 x 24 x 26 = 13728. There we go.
So, the three numbers are 22, 24, 26.
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