Science, asked by bachewaradithi1, 1 month ago

138÷[35-{53-(89-72÷9×6)}]=?

Answers

Answered by itzheartcracker13
1

138÷[35-{53-(89-72÷9×6)}]

Step-1: Parts of the equation enclosed in 'Brackets' must be solved first, and inside the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

138 ÷ [35 – {53 – (89 – 72 ÷ 9 × 6)}]

138 ÷ [35 – {53 – (89 – 8 × 6)}]

138 ÷ [35 – {53 – (89 – 48)}]

138 ÷ [35 – {53 – 41]

138 ÷ [35 – 12]

138 ÷ 23 = 6

Answered by sudhirsingh0779
0

Answer:

138÷(35-(53-(89-8*6)

138÷(35-(53-41)

138÷(35-12)

138÷23

6

Explanation:

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138÷[35-{53-(89-72÷9×6)}]

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