Question

13b 12. Construct a rhombus ABCD whose side AB = 5 cm and diagonal AC = 7.6 cm. 13. Construct a square each of whose sides measures 5.8 cm. 14. Construct a square each of whose diagonals measures 6.6 cm.​

Answer 1

Step-by-step explanation:

We know that, diagonals of a rhombus are perpendicular bisectors of each other.

Using the same property, follow the below steps to construct a rhombus ABCD:

1. Draw AC=6.3 cm

2. Draw perpendicular bisector XY of AC intersecting AC at O.

3. Taking O as centre and

2

1

×5.8=2.9 cm as radius,

draw two arcs intersecting OX and OY at points B and D respectively.

4. Join AB, BC, CD and AD.

The figure ABCD is the required rhombus.

solution