Question

13b+c
Given that a=
b-c '
(i) make b the subject of the formula,
(ii) find the value of b when a = 2 and c=5.
V 6-

Answer 1

Answer:

please mark it as brainliest and thank even follow if possible

Answer 2

Answer:

I)

$b = \frac{c( {a}^{2} + 1)}{( {a}^{2} - 3)}$

ii)

$\frac{25}{3}$

Step-by-step explanation:

(I)

$a = \sqrt{ \frac{3b + c}{b - c} } \\ {a}^{2} = \frac{3b + c}{b - c} \\ {a}^{2} b - {a}^{2} c = 3b + c \\ {a}^{2} b - 3b = {a}^{2} c + c \\ b( {a}^{2} - 3) = c( {a}^{2} + 1) \\ b = \frac{c( {a}^{2} + 1)}{( {a}^{2} - 3)}$

(ii)

$b = \frac{c( {a}^{2} + 1)}{( {a}^{2} - 3)} \\ b = \frac{5( {2}^{2} + 1)}{ {2}^{2} - 1} = \frac{5 \times 5}{4 - 3} = \frac{25}{1} = 25$

Thank you. Please mark me as brainliest.