Question

13t-4(t+8)-4=0
Please answer this for me....

Answer 1

Answer:

4

Step-by-step explanation:

13t - 4(t + 8) - 4 = 0

13t - 4t - 32 - 4 = 0

9t - 36 = 0

9t = 36

t = 36/9

t = 4

Answer 2

Answer :-

• The value of t is 4.

Solution :-

$\longrightarrow\sf13t - 4 \: (t + 8) - 4 = 0$

Removing the brackets,

$\longrightarrow\sf13t - 4t - 32 - 4 = 0$

$\longrightarrow\sf9t - 32 - 4 = 0$

$\longrightarrow\sf9t - 36 = 0$

Transposing -36 from LHS to RHS, changing it's sign,

$\longrightarrow\sf9t = 0 + 36$

$\longrightarrow\sf9t = 36$

Transposing 9 from LHS to RHS, changing it's sign,

$\longrightarrow\sf t = \dfrac{36}{9}$

$\longrightarrow\sf t = 4$

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V E R I F I C A T I O N

• To check our answer, let's put 4 in the place of t and see whether LHS = RHS.

LHS

$\longrightarrow\rm13t - 4 \: (t + 8) - 4$

$\longrightarrow\rm13 \times 4 - 4 \: (4 + 8) - 4$

$\longrightarrow52 - 4 \: (4 + 8) - 4$

$\longrightarrow\rm52 - 16 - 32 - 4$

$\longrightarrow\rm0$

RHS

$\longrightarrow0$

LHS = RHS.

Hence verified!!

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