Math, asked by arnavmanesh, 3 days ago

13th term of an arithmatic sequence is 40. a. What is the sum of its 6th term and 20th term. b. What is the sum of its first 25 terms.​

Answers

Answered by lalitmandrai
2

Answer:

13th term of an arithmatic sequence is 40.

a13 = a + 12d = 40

a. What is the sum of its 6th term and 20th term.

s =  \frac{a1 +  5d+ a1 + 19d}{2}  \\ s =  \frac{2a1 + 24d}{2}  \\ s = a1 + 12d

b. What is the sum of its first 25 terms.

s =  \frac{a1 + 24d}{2}  \\

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