Question

13x²+2xy-z² × 2x²+5
​

Answer 1

Answer:

I hope correct

Step-by-step explanation:

Factorisation of x^2+y^2-z^2-2xyx

2

+y

2

−z

2

−2xy is (x-y+z)(x-y-z).

Step-by-step explanation:

We have to factorise,

x^2+y^2-z^2-2xyx

2

+y

2

−z

2

−2xy

= x^2+y^2-2xy-z^2\ [(a-b)^2 =a^2+b^2-2ab]

2

+y

2

−2xy−z

2

[(a−b)

2

=a

2

+b

2

−2ab]

= (x-y)^2-z^2\ [(a-b)(a+b)=a^2-b^2](x−y)

2

−z

2

[(a−b)(a+b)=a

2

−b

2

]

= (x-y+z)(x-y-z)

Hence,factorisation of x^2+y^2-z^2-2xyx

2

+y

2

−z

2

−2xy is (x-y+z)(x-y-z).