(−13x2+5x+ 14+(-19x2-20x+8)
Answers
Answer:
Step-by-step explanation:
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(((0-(13•(x2)))-5x)-14)+(((0-(2•7x2))-20x)+8)
STEP
2
:
Equation at the end of step
2
:
(((0 - 13x2) - 5x) - 14) + (-14x2 - 20x + 8)
STEP
3
:
STEP
4
:
Pulling out like terms
4.1 Pull out like factors :
-27x2 - 25x - 6 = -1 • (27x2 + 25x + 6)
Trying to factor by splitting the middle term
4.2 Factoring 27x2 + 25x + 6
The first term is, 27x2 its coefficient is 27 .
The middle term is, +25x its coefficient is 25 .
The last term, "the constant", is +6
Step-1 : Multiply the coefficient of the first term by the constant 27 • 6 = 162
Step-2 : Find two factors of 162 whose sum equals the coefficient of the middle term, which is 25 .
-162 + -1 = -163
-81 + -2 = -83
-54 + -3 = -57
-27 + -6 = -33
-18 + -9 = -27
-9 + -18 = -27
For tidiness, printing of 14 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
-27x2 - 25x - 6