Question

14+1/5[{-10×(25-13-3)}÷(-5)]

Answer 1

14+1/5[{-10×(25-13-3)}÷(-5)]
14+1/5[{-10×9÷(-5)]
14+1/5×18
70+18÷5
88÷5

Answer 2

Answer:

$14+\frac{1}{5}\left[\left\{-10\times \left(25-12-3\right)\right\}\right]\div \left(-5\right)=\frac{88}{5}$

Step-by-step explanation:

Given : $14+\frac{1}{5}\left[\left\{-10\times \left(25-13-3\right)\right\}\right]\div \left(-5\right)$

We will solve using BODMAS

B denotes bracket

O denotes Order

D denotes division

M denotes multiplication

A denotes addition

S denotes Subtraction

Rewriting given expression as

$=14+\frac{1}{5}\times \frac{-10\left(25-13-3\right)}{-5}$

Solving brackets, we get,

$=14+(\frac{1}{5}\times \frac{-10\left(25-16\right)}{-5})$

$=14+(\frac{1}{5}\times \frac{10 \times 9}{5})$

$=14+(\frac{1}{5}\times 18 }$

$=14+\frac{18}{5}$

$=\frac{88}{5}$