Question

14 10 the no. of neutron in 28 gram of c14 ​

Answer 1

Answer:

The number of neutrons is equal to the difference in the mass number and atomic number.

It is equal to 14−6=8.

(a) The number of neutrons present in 7 mg of C-14:

     =  

14

7×10  

−3

 

​

×6.02×10  

23

×8

     

     =2.408×10  

21

 neutrons

(b) Total mass of neutrons in 7 mg of C-14:  

=2.4088×10  

21

×1.675×10  

−27

 

=4.035×10  

−6

  kg.