Question

ಒಂದು ಸಮಾಂತರ ಶ್ರೇಡಿಯ ಎರಡನೇ ಮತ್ತು ಮೂರನೇ ಪದಗಳು ಕ್ರಮವಾಗಿ 14 ಮತ್ತು 18 ಆದರೆ ಇವತ್ತು ಒಂದರ ಪದಗಳ ವರೆಗೆ ಮತವನ್ನು ಕಂಡುಹಿಡಿಯಿರಿ
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Answer 1

Step-by-step explanation:

Given The second and third term of an A.P are 14 and 18 respectively. Find the sum of first 51 terms

• Now the second term of A.P is 14
• So we have n = 2 and a2 = 14
•      an = a + (n – 1)d  
•      a2 = a + (n – 1) d
•      14 = a + (2 – 1) d
•      14 = a + d
•         a = 14 – d
• Now the third term of A.P is 18
• So we have n = 3 and a2 = 18
•      an = a + (n – 1)d  
•      a2 = a + (n – 1) d
•      18 = a + (3 – 1) d
•      18 = a + 2d
•         a = 18 – 2d
• So we get the two equations as  
•    a = 14 – d and a = 18 – 2d
•    Equating  we get
•     14 – d = 18 – 2d
•     2d – d = 18 – 14
•         Or d = 4
• Now substituting the value of d we get
•            a = 14 – d
•            a = 14 – 4
•            a = 10
• So we have sum to n terms is given by
• Sn = n/2 (2a + (n – 1) d
•       We have n = 51, a = 10 and d = 4
•  Sn = 51 / 2 (2(10) + (51 – 1) 4
•        = 51 / 2 (20 + 200)
•       = 51 / 2 (220)
•        = 5610
• Therefore the sum of first 51 terms is 5610

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Answer 2

Answer:

Step-by-step explanation: