Question

14.1f 3, x+1,5 are in A.P, the find the value of 'x'.​

Answer 1

Answer:

AP is 3, x + 1, 5

a1 = 3, a2 = x + 1, a3 = 5

a2 - a1 = d ___(i)

a3 - a2 = d ___(ii)

a2 - a1 = a3 - a2

x + 1 - 3 = 5 - (x + 1)

x - 2 = 5 - x - 1

x + x = 5 - 1 + 2

2x = 6

x = 3

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Answer 2

Answer:

X=3

Step-by-step explanation: