Question

14.Findthevalueofksothatthefollowingsystemofequationshasinfinitesolutions.3x-y-6=0 , 6x-2y+k=0​

Answer 1

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Answer 2

Answer:

k = -12

Step-by-step explanation:

a equation having infinite solution should be such that a1/a2 = b1/b2 = c1/c2

In 3x-y-6=0 a1= 3, b1= -1, c1= -6

In 6x-2y+k=0 a1= 6, b1= -2, c1 = k

so, a1/a2 = 3/6 = 1/2

b1/b2 = -1/-2 = 1/2

so c1/c2 = -6/k = 1/2

k = -6×2 = -12