Question

14.2g of Na2SO4 is added to form 800 ml of solution.what is the molarity of solution?​

0.125


0.25


0.40


0.65

Answer 1

Answer:

0.125

Explanation:

I am not sure about the answer

Answer 2

Thus the molarity of the solution is 0.125 M.

Explanation:

• Mass of Na₂SO₄ = 14.2 g
• Mass of one mole of Na₂SO₄ = 142.04 g / mol ~ 142 g/mol
• Number of moles of Na₂SO₄ = Mass of substance Na2SO4 / Mass of one mole of substance Na2SO4

Number of moles of Na₂SO₄  = 14.2 / 142 = 0.1  moles

Volume of solution = 800 ml = 800 / 1000 = 0.8 litre

Molarity of solution = Moles of solute / Volume of solution in liter

Molarity of solution = 0.1 / 0.8 = 0.125