Question

14+3{34-18-16}÷3[6×2+17-(7×2)]

Answer 1

using the formulae of BODMAS

=14 + 3 {34-18-16} ÷ 3 [6×2+17-(7×2)]

=14 + 3 {34-34} ÷ 3 [6×2 + 17- 14 ]

=14 + 3×0 ÷ 3 [12 + 17 - 14]

=14 + 3×0 ÷ 3 [15]

$14 + 3 \times 0 \div 3 \times 15 \\ \\ 14 + 3 \times \frac{0}{3} \times 15 \\ \\ 14 + 0 \\ \\ 14$

Answer 2

Answer:

Step-by-step explanation:

=14 + 3 {34-18-16} ÷ 3 [6×2+17-(7×2)]

=14 + 3 {34-34} ÷ 3 [6×2 + 17- 14 ]

=14 + 3×0 ÷ 3 [12 + 17 - 14]

=14 + 3×0 ÷ 3 [15]

14 + 3 \times 0 \div 3 \times 15 \\ \\ 14 + 3 \times \frac{0}{3} \times 15 \\ \\ 14 + 0 \\ \\ 14