Question

14. 3 gm Mg reacts with 2 gm of Sulphur to form magnesium sulphide (MgS). Amount of Mg left. unreacted is (2) 1.0 g (1) 0.5 g (3) 1.5 g (4) 2.5 g ​

Answer 1

Answer:

1.5

Explanation:

The ratio of mass between magnesium and sulfur is :- 3:4

According to your question we need to find the amount of magnesium which reacts with 2g of sulfur

Now ,

=> 3 : 4 :: x : 2

=> 4x = 2×3

=> 4x = 6

=> x = 6/4 = 1.5

Hence 1.5 g of magnesium reacts with 2g sulfur and 3g - 1.5g = 1.5 g of magnesium left.