Question

14(3X-5Y)^3 + 7(3X-5Y)^2

Answer 1

The factorisation of $14(3X-5Y)^3 + 7(3X-5Y)^2$ = = 7(3x - 5y)(3x - 5y)(6X - 15Y + 1) or, 7$(3X - 5Y)^2$[6X - 15Y + 1]

Step-by-step explanation:

The given expression:

$14(3X-5Y)^3 + 7(3X-5Y)^2$

To find, the factorisation of $14(3X-5Y)^3 + 7(3X-5Y)^2$ = ?

∴ $14(3X-5Y)^3 + 7(3X-5Y)^2$

Taking 7$(3X - 5Y)^2$, we get

= 7$(3X - 5Y)^2$[2(3X - 5Y) + 1]

= 7$(3X - 5Y)^2$[6X - 15Y + 1]

= 7(3x - 5y)(3x - 5y)(6X - 15Y + 1)

∴ The factorisation of $14(3X-5Y)^3 + 7(3X-5Y)^2$ = = 7(3x - 5y)(3x - 5y)(6X - 15Y + 1) or, 7$(3X - 5Y)^2$[6X - 15Y + 1]

Answer 2

Answer:

7(3x – 5y)2 (6x – 10y + 1)

Step-by-step explanation:

=7(3x – 5y)2 [2(3x – 5y) +1]

= 7(3x – 5y)2 (6x – 10y + 1)

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