Math, asked by shubhavamshi91181, 5 days ago

14(3y-5z)³+25x³y²z+35x²y²z²

Answers

Answered by preeti353615
0

Answer:

14(3y-5z)³+25x³y²z+35x²y²z² = 378 y³ - 1890 x y²   +25x³y²z+35x²y²z² + 2100y z² - 350z³

Step-by-step explanation:

Formula: (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3

14(3y-5z)³+25x³y²z+35x²y²z²

= 14[(3y)³ - 3 (3y)² (5z) + 2 (3y)(5z)² - (5z)³ ] +25x³y²z+35x²y²z²

= 14[27y³ - 15x (9y²)   + 6y (25z²) - 25z³ ] +25x³y²z+35x²y²z²

= 14[27y³ - 135x y²   + 150y z² - 25z³ ] +25x³y²z+35x²y²z²

= 378 y³ - 1890 x y²   + 2100y z² - 350z³   +25x³y²z+35x²y²z²

= 378 y³ - 1890 x y²      +25x³y²z+35x²y²z² + 2100y z² - 350z³

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