Question

14 (3y-5z)^3+7 (3y-5z)^2 factorise it

Answer 1

=14(3y-5z)³+7(3y-5z)²

={7(3y-5z)²}{2(3y-5z) +7}

={7(9y²+25z²-30zy)}{6y-10z+7}

=(63y²+175z²-210zy) (6y-10z+7)

I hope this much will help you

Answer 2

Answer:

$14(3y-5z)^3+7(3y-5z)^2=7(3y - 5z)^2(6y - 10z + 1)$

Step-by-step explanation:

Given : Expression $14(3y-5z)^3+7(3y-5z)^2$

To find : Factories the expression ?

Solution :

To factor the expression we have to take common from terms,

$14(3y-5z)^3+7(3y-5z)^2=7[2(3y - 5z)^3 + (3y - 5z)^2]$

$14(3y-5z)^3+7(3y-5z)^2=7(3y - 5z)^2[2(3y - 5z) + 1]$

$14(3y-5z)^3+7(3y-5z)^2=7(3y - 5z)^2[2(3y) - 2(5z) + 1]$

$14(3y-5z)^3+7(3y-5z)^2=7(3y - 5z)^2(6y - 10z + 1)$

Therefore, $14(3y-5z)^3+7(3y-5z)^2=7(3y - 5z)^2(6y - 10z + 1)$