Math, asked by Rosalindsahu, 1 year ago

14(3y-5z)(3y-5z)(3y-5z)+7(3y-5z)(3y-5z)

Answers

Answered by TooFree
35

Answer:

(3y - 5z)²(6y - 10z + 1)


Step-by-step explanation:

14(3y-5z)(3y-5z)(3y-5z)+7(3y-5z)(3y-5z)


Since (3y - 5z) repeats twice in every term, we put them together:

14(3y-5z)²(3y-5z)+7(3y-5z)²


Taking out common factors 7(3y - 5z)²:

7(3y - 5z)²( 2 (3y - 5z) + 1)


Distribute 2:

(3y - 5z)²(6y - 10z + 1)


Answer: (3y - 5z)²(6y - 10z + 1)


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