Question

14,48,50 r Pythagorean triplets

Answer 1

Answer:

2k, (k

2

+1) and (k

2

−1) form a Pythagorean triplet for any number, k > 1

Let 2k=14

Hence, k=7

and, k

2

+1=7

2

+1=49+1=50

and, k

2

−1=7

2

−1=49−1=48

Check the answers: 14

2

+48

2

=196+2304=2500=50

2

Hence, the triplet is 14,48,50

Step-by-step explanation:

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