Question

14. 5+ * 3 2x z. y - 6 3 - 2y 2 5 QUATIONS TO PR​

Answer 1

Answer:

Solve the following equations: 2x – y + z = –3 2x + 2y + 3z = 2 3x – 3y – z ... 6x - 6y - 2z - 6x - 6y - 9z = -8 - 6.

Missing: 5+

We have to solve the following set of equations: 2x – y + z = –3...(1) 2x + 2y + 3z = 2...(2) 3x – 3y – z = –4 ...(3) (2) - (1) =>2x + 2y + 3z .

Answer 2

x + y + z = 0...(1)

x + y + z = 0...(1)2x + 3y + z = 0 ...(2)

x + y + z = 0...(1)2x + 3y + z = 0 ...(2)x + 2y = 0 ... (3)

x + y + z = 0...(1)2x + 3y + z = 0 ...(2)x + 2y = 0 ... (3)From equation (3), we have

x + y + z = 0...(1)2x + 3y + z = 0 ...(2)x + 2y = 0 ... (3)From equation (3), we havex = - 2y

x + y + z = 0...(1)2x + 3y + z = 0 ...(2)x + 2y = 0 ... (3)From equation (3), we havex = - 2yPutting this value of x in equations (1), we

x + y + z = 0...(1)2x + 3y + z = 0 ...(2)x + 2y = 0 ... (3)From equation (3), we havex = - 2yPutting this value of x in equations (1), weget - 2y + y + z = 0 y = z

x + y + z = 0...(1)2x + 3y + z = 0 ...(2)x + 2y = 0 ... (3)From equation (3), we havex = - 2yPutting this value of x in equations (1), weget - 2y + y + z = 0 y = zHence x = - 2z

x + y + z = 0...(1)2x + 3y + z = 0 ...(2)x + 2y = 0 ... (3)From equation (3), we havex = - 2yPutting this value of x in equations (1), weget - 2y + y + z = 0 y = zHence x = - 2zThus, the solution of the given system of equations is (-2z, z, z), where z is a parameter (Z R). Hence the system has infinite number of solutions including zero solution.