Question

14\5√3-√5 rationalize the denominator.​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$= \frac{14}{5 \sqrt{3} - \sqrt{5} } \\ = \frac{14}{5 \sqrt{3} - \sqrt{5} } \times \frac{5 \sqrt{3} + \sqrt{5}}{5 \sqrt{3} + \sqrt{5} } \\ = \frac{14( 5 \sqrt{3} + \sqrt{5}) }{ {( 5 \sqrt{3} + \sqrt{5})}^{2} } \\ = \frac{70 \sqrt{3} + 14 \sqrt{5} }{(25 \times 3) + 5} \\ = \frac{70 \sqrt{3} + 14 \sqrt{5} }{80} \\ = \frac{35 \sqrt{3} + 7 \sqrt{5} }{40}$