Math, asked by amita62, 15 days ago

14.5 litres of wine replaced from a filled
container of oil and filled with water.
It is repeated again. Now the ratio
of wine and water becomes
25 : 11. Find the capacity of the
container
[NET, 1998]​

Answers

Answered by meghapatel722
0

Answer:

5 litres of wine is replaced from a filled container of oil and filled with water. It is repeated again. Now the ratio of wine and water becomes 25:11. What is the capacity of the container?

6 Answers

Sushil Parwani, former Retired Since 2014

Answered 10 months ago · Author has 1K answers and 67.8K answer views

How is wine removed from a container of OIL?

However assuming it is a container of wine with capacity x

After removing 5 litres of wine and replacing with 5 litres water container x-5 litres wine and 5 litres water.

when process is repeated

wine removed (x-5)/x .5=5-25/x

wine left=(x-5)-5+25/x=x-10+25/x

water in container=x-wine left

=10–25/x

Ratio wine to water=(x-10+25/x)/(10–25/x)=25/11

(x-10+25/x).11=(10–25/x) .25

(x^2–10x+25).11=(10x-25).25

11x^2–110x+275=250x-625

11x^2–360x+900=0

x= 30 litres

other value 30/11 is neglected as it is less than 5 litres and 5 litres are to be drawn out

Answered by Anonymous
0

Hope it helps!! Mark this answer as brainliest if u found it useful and follow me for quick and accurate answers...

Let the capacity of the wine container or the original quantity of wine in the container be X

Then the quantity of wine left in the container after two operations = x[1 -  \frac{5}{x}

The new ratio of wine to water is given as 25:11

Now, in order to get the quantity of wine we will write an equation as

 \frac{ quantity  \:  \: of \:  \:  wine \:  \:  left \:  \:  in  \:  \: the \:  \:  vessel}{original \:  \:  quantity  \:  \: of \:  \:  wine \:  \:  in \:  \:  the \:  \:  vessel } =   \frac{new \:  \:  quantity \:  \:  of  \:  \: wine}{ total \:  \:  quantity \:  \:  of  \:  \: mixture }

 \frac{[x(1 -  \frac{5}{x}  {}^{2} ]}{x} =  \frac{25}{25 + 11}  \\  \\  {(1 -  \frac{5}{x} )}^{2}  =  \frac{25}{36}  \\  \\ taking \:  \: square \:  \: roots \:  \: both \: sides \:  \:  \\  \\ 1 -  \frac{5}{x}  =  \frac{5}{6}  \\  \\ 6(x - 5) = 5x \\  \\ 6x - 30 = 5x \\  \\ 6x - 5x = 30 \\  \\ x = 30 \:  \: litres

Thus, capacity of wine container is 30 litres

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