14.5 litres of wine replaced from a filled
container of oil and filled with water.
It is repeated again. Now the ratio
of wine and water becomes
25 : 11. Find the capacity of the
container
[NET, 1998]
Answers
Answer:
5 litres of wine is replaced from a filled container of oil and filled with water. It is repeated again. Now the ratio of wine and water becomes 25:11. What is the capacity of the container?
6 Answers
Sushil Parwani, former Retired Since 2014
Answered 10 months ago · Author has 1K answers and 67.8K answer views
How is wine removed from a container of OIL?
However assuming it is a container of wine with capacity x
After removing 5 litres of wine and replacing with 5 litres water container x-5 litres wine and 5 litres water.
when process is repeated
wine removed (x-5)/x .5=5-25/x
wine left=(x-5)-5+25/x=x-10+25/x
water in container=x-wine left
=10–25/x
Ratio wine to water=(x-10+25/x)/(10–25/x)=25/11
(x-10+25/x).11=(10–25/x) .25
(x^2–10x+25).11=(10x-25).25
11x^2–110x+275=250x-625
11x^2–360x+900=0
x= 30 litres
other value 30/11 is neglected as it is less than 5 litres and 5 litres are to be drawn out
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Let the capacity of the wine container or the original quantity of wine in the container be X
Then the quantity of wine left in the container after two operations = x[]²
The new ratio of wine to water is given as 25:11
Now, in order to get the quantity of wine we will write an equation as
Thus, capacity of wine container is 30 litres