14. (a) AM is a median of a triangle ABC. Prove that AB + BC + CA» 2 AM
B В
M
(b) Evaluate 3 - (5 - 6 + 3)
{e} Solve the following equations:
3(y - 2) = 2ly - 1) - 3
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1
Answer:
, In triangle ABM
AB+BM>AM ..................... (1)
In triangle AMC
MC+AC>AM ...................... (2)
Add (1) and (2),
AB+(BM+MC)+AC>AM+AM
AB+BC+AC>2AM
So, the statement is true.
Solve -
3(y−2)=2(y−1)−3
=>3y−6=2y−2−3
=>3y−2y=−5+6
=>y=1
No 2 Evaluate i can't do it
Hope it helps and follow me.
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