Math, asked by namitavarshney22, 2 days ago

14 A bag contains 12 red, 10 blue, 21 green and 7 white balls. What is the probability of
taking out one blue ball? (1 ​

Answers

Answered by Ooguay
2

Answer:

\frac{1}{5}

Step-by-step explanation:

Total no of balls = 12 + 10 + 21 + 7 = 50

∴ Probability of taking out one blue ball = \frac{10}{50} = \frac{1}{5}

Answered by ramjeetsingh03997
1

Answer:

probability- number of favourable outcomes/ total number of outcomes

total outcomes =12 +10+21+7=50

  • probability of getting one blue ball =10\50=1/5
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