Question

14.A bag contains a mixture of 8 Rupee, 6 Fifty paise and 4 twenty-five paise coins. In how many ways selection of 3 coins can be made so that.
1)All three are rupee coin 2)One of each denomination 3)None is a rupee coin​

Answer 1

$i. \frac{8}{18} = \frac{2}{9} \\ ii. \frac{18}{18} = 1 \\ iii. \frac{10}{18} = \frac{5}{9}$

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