Question

14. A bag contains red and black balls, if 5 black balls are added and 7 red balls are removed
from the bag, the number of red balls and black balls will be equal. If 3 red balls are removed,
the number of red balls will be 1 more than double the number of black balls. How many
balls of each type are there?​

Answer 1

Answer:

Number of red balls is equal to 20 and number of black balls is equal to 8

Step-by-step explanation:

Let the number of red balls be X and black balls be Y

Y+5 = X-7

X = Y+12

X-3 = 2Y+1

X = 2Y+4

Therefor,

Y+12 = 2Y+4

12-4 = 2Y-Y

8 = Y

X = 2Y+4

= 2×8 +4

= 16+4

= 20

Therefor Number of red balls is equal to 20 and number of black balls is equal to 8