Physics, asked by kumarranapranav, 5 months ago

14. A body of mass 5 kg is moving with a velocity of 10 m/s. It is acted upon by a force 20 N in
the direction of motion. Whạt will be its velocity after 1 second?
[Ans. 14 m/s]

Answers

Answered by Ayodhyavasi

Answer:

Answer: v = 14 m/s

Explanation:

mass m = 5 kg

initial velocity u = 10 m/s

force F = 20N

time taken = 1 sec

we have to find out final velocity v = ?

then by first equation of motion

v = u + at ..........(i)

first of all we will find ' a '

$\: \: \: \: \: a = \frac{f}{m}$

$\: \: \: \: \: a = \frac{f}{m}$ $\: \: \: \: a = \frac{20}{5}$

$\: \: \: \: \: a = \frac{f}{m}$ $\: \: \: \: a = \frac{20}{5}$ $\: \: \: \: \: a = 4 \: \: m. {sec}^{ - 2}$

$\: \: \: \: \: a = \frac{f}{m}$ $\: \: \: \: a = \frac{20}{5}$ $\: \: \: \: \: a = 4 \: \: m. {sec}^{ - 2}$ from equation (i) ,we get

$\: \: \: \: \: a = \frac{f}{m}$ $\: \: \: \: a = \frac{20}{5}$ $\: \: \: \: \: a = 4 \: \: m. {sec}^{ - 2}$ from equation (i) ,we get v = 10 + 4 × 1

$\: \: \: \: \: a = \frac{f}{m}$ $\: \: \: \: a = \frac{20}{5}$ $\: \: \: \: \: a = 4 \: \: m. {sec}^{ - 2}$ from equation (i) ,we get v = 10 + 4 × 1 v = 10 + 4

$\: \: \: \: \: a = \frac{f}{m}$ $\: \: \: \: a = \frac{20}{5}$ $\: \: \: \: \: a = 4 \: \: m. {sec}^{ - 2}$ from equation (i) ,we get v = 10 + 4 × 1 v = 10 + 4 v = 14 m/sec

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Answered by Anonymous

Answer:

Answer

M=5kg

$\color {red} \tt \ a = \frac{v - u}{t}$

$\huge \color{purple} \tt \frac{v - 10}{1}$

f=20N

f=m×a

20N=5kg×(V−10)

4=(v−10)

$\huge \color{magenta} \tt \boxed {v = 14}$

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14. A body of mass 5 kg is moving with a velocity of 10 m/s. It is acted upon by a force 20 N inthe direction of motion. Whạt will be its velocity after 1 second?[Ans. 14 m/s]​