14.
A capacitor of capacitance of 10 uF, charged to
100 V is connected to an uncharged capacitor.
The effective potential is 40 V. The capacitance of
uncharged capacitor is
(1) 5 uF
(2) 10uF
(3) 15 uF
(4) 30 uF
Answers
Answered by
16
Answer:
Initial charge on the capacitor Q1 = C1V1
Q1 = 10uF x 100V
Finally this capacitor is connected with another charge less capacitor.
The effective voltage given is 40V.
Since both the capacitors are joined, they should have same potential.
By conservation of charge : sum of the charges after redistribution on two capacitors equals the initial charge on the first capacitor.
Q1 = q1+q2
C1V1 = (C1 + C2)Veffective
10uF x 100V = (10uF + C2) x 40V
25uF = 10uF + C2
C2 = 15uF
Option (3)
Answered by
1
Answer: option (3)
Explanation:
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