Question

14 a constant force acting on a body of mass 3kg changes its speed from 2 to 3.5ms-1 in 25 seconds. what is the magnitude of the applied force?

Answer 1

Answer:

0.18N

Explanation:

Rate of change in momentum is known as Force, according to Newton's Second Law, hence if we apply that:

Given,

m=3kg, v1=2m/s, v2=3.5m/s, t=25s

F=(p2-p1)/t

We know p=mv.

Therefore, p1=m*v1=3*2=6kgm/s, p2=m*v2=3*3.5=10.5kgm/s

F=(10.5-6)/25=0.18N