Question

14.
A force acting on a particle of mass 200g displaces it through 400 cm in 2s. If the initial velocity
particle is zero, then the magnitude of the force is
b) 4N
d) 400 N
a) 0.4 N
c) 40 N​

Answer 1

$\huge{\boxed{\mathcal\pink{\fcolorbox{red}{yellow}{Answer!!...}}}}$

____________

0.4 N...

______________

mass=m=200g=0.2kg

distance =s=400cm=4cm

time =t=2sec

u = 0m/s

find f = ?

By second law of motion,

S=ut+1/2at^2

=> 0+1/2×a×4=4

=> a=2m/s^2

By second equation of motion,

F=ma

=> 0.2×2=0.4N

Therefore, Magnitude of force is 0.2N...

hope!!...it helps uhh...✌️❣️