Question

14. A gas balloon has volume of 106 litres when the temperature is 42 deg celsius and pressure is 740.0 mm of mercury. What will its volume be at 20 deg celsius and 780 mm of mercury pressure ​

Answer 1

Answer :-

Required volume is 93.6 Litres .

Explanation :-

We have :-

→ Initial volume (V₁) = 106 L

→ Initial temperature (T₁) = 42°C

→ Initial pressure (P₁) = 740 mm Hg

→ Final temperature (T₂) = 20°C

→ Final pressure (P₂) = 780 mm Hg

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Firstly, let's convert the units of initial and final temperature from °C to K .

Initial temperature :-

⇒ 0°C = 273 K

⇒ 42°C = 273 + 42

⇒ 315 K

Final temperature :-

⇒ 20°C = 273 + 20

⇒ 293 K

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Now, putting the values in the "Combined Gas Equation", we get :-

P₁V₁/T₁ = P₂V₂/T₂

⇒ (740 × 106)/315 = (780 × V₂)/293

⇒ 78440/315 = 2.66V₂

⇒ 249 = 2.66V₂

⇒ V₂ = 249/2.66

⇒ V₂ = 93.6 L

Answer 2

Explanation:

topic :

volume

given :

A gas balloon has volume of 106 litres when the temperature is 42 deg celsius and pressure is 740.0 mm of mercury. What will its volume be at 20 deg celsius and 780 mm of mercury pressure

to find :

What will its volume be at 20 deg celsius and 780 mm of mercury pressure

solution :

• A gas balloon has volume = 106 litre

• the temperature = 42 deg celsius

• gas of balloon pressure = 740

• volume of mercury = 20 degree Celsius

• pressure of mercury = 780

• gas balloon has volume

• first we will find the c and k

• the answer is = 315 k

• second mercury pressure

• so the k value first we add the number the answer = 293 k

• then we will do formula writing formula is

• P₁V₁/T₁= P₂V₂/T₂

• 78440/315 = 2.66Volume

• 249 = 2.66V₂

• Volume= 249/2.66

• Volume= 93.6 L