14. A has 2 elements, B has 4 elements and A
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There are 24 ways of mapping an injective function from A to B. The answer is option-C. 4P3=4!
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Answer:
Correct option is A)
Given, n(A)=4,n(B)=2
∴n(A×B)=8
Thus the number of subsets of A×B having at least 3 elements
=2^(8-8) C_0^(-8)C_2 = 256−1−8−28=219
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