Question

14. A housewife, with a given amount, can buy either
10 apples or 15 oranges or 2 watermelons. Find the
maximum number of oranges she can buy with six
times the initial amount such that she gets each of the
(B) 81
three varieties of fruits.
(A) 75
(C) 60
(D) 72.​

Answer 1

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A housewife, with a given amount, can buy either

10 apples or 15 oranges or 2 watermelons. Find the

maximum number of oranges she can buy with six

times the initial amount such that she gets each of the

(B) 81

three varieties of fruits.

(A) 75

(C) 60

(D) 72.

$\huge{\mathcal{\purple {A}\green{N}\pink{S}\blue{W}\purple {E}\green{R}\pink{!}}}$

Let the initial amount =A

Cost of 1 apple =(A/10)

Cost of 1 orange =(A/15)

Cost of 1 watermelon =(A/2)

As all three types of fruits are bought, the minimum shall be one.

As oranges are to be maximum, others are one each.

Amount spent =6A(as per data).

Hence,

the number of oranges

=[6A– {(A/10) + (A/2)}] / (A/15)

=[6A– (6A/10)] / (A/15)

=(54A/10) / (A/15)

=81

Hence, the correct option is (B).