Physics, asked by Anonymous, 7 months ago

14. A jeweller claims that he makes ornament of pure
gold of relative density 19-3. He sells a bangle
weighing 25-25 gf to a person. The clever customer
weighs the bangle when immersed in water and
finds that it weighs 23-075 gf in water. With the
help of suitable calculations find out whether the
ornament is made of pure gold or not.
[Hint : Calculate R.D. of material of bangle which
comes out to be 11-6).​

Answers

Answered by sonisingh26119
24

❤️Hii mele intelligent bhaiyaaa❤️

ANSWER:- <font color = black >

The 25,25 - 23.07 = 2.18 g.

Density=Mass/Volume.

Mass of displaced water = 2.18g.

Density = 1g/cc.

Hence, the volume of the water displaced is 2.18cc

let calculate the density of the ornament.

Mass = 25.25g, Volume = 2.18cc and Density = 2.18/25.25 =11.58g/cc

Jeweler stated the density of gold 19.3g/cc.

Hence, the gold is not pure..

❤️❤️

Answered by hmangla41
2

Answer:

❤️

ANSWER:-< font color = black ><fontcolor=black>

The 25,25 - 23.07 = 2.18 g.

Density=Mass/Volume.

Mass of displaced water = 2.18g.

Density = 1g/cc.

Hence, the volume of the water displaced is 2.18cc

let calculate the density of the ornament.

Mass = 25.25g, Volume = 2.18cc and Density = 2.18/25.25 =11.58g/cc

Jeweler stated the density of gold 19.3g/cc.

Hence, the gold is not pure..

❤️❤️

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