Question

14. A man goes 12 m due east and then 5m north. Find distance from the starting point.​

Answer 1

Answer:

displacement 13 m, distance 17 m

Step-by-step explanation:

solution given in figure,,,,

Answer 2

In the given attachment,

A represents the initial position of the man.

B represents the position of the man 12m east.

C represents the final position.

To Find:

The distance of the man from the starting point.

Solution:

By using Pythagoras Theorem, we get

AC = √AB^2 + BC^2

AC = √12^2 + 5^2

AC = √144 + 25 = √169

AC = 13 m

Answer:

The man is 13 m away from his starting point.