Physics, asked by ak34567825, 1 day ago

14. A nut can be opened by a lever of length 0.25 m by applying a force of 80N. What should be the length of lever, if a force of 32 N is enough to open the nut?​

Answers

Answered by 604ayushmishra
6

Answer:

Explanation:

Hi,

The turning effect is the same in both the case

τ1 = τ2  

Load × Lever arm = Load × Lever length

80 N × 0.25 × 10-2 =  32 × Lever length

Lever length = (80 N × 0.25 × 10-2) / 32

Lever length = 0.625 m = 62.5 cm

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