Question

14. A parallel plate air capacitor has capacitance C.
Now half of the space is filled with a dielectric
material with dielectric constant K = 5 as shown
in figure. The new capacitance is ​

Answer 1

hope this is solved..............

Answer 2

Concept:

Capacitor: The device that stores electrical energy in an electric field is known as a capacitor.

The ratio of the quantity of electric charge held on a conductor to an electric potential difference is known as capacitance.

Given:

A parallel plate air capacitor has capacitance $C$.

Half of the space is filled with a dielectric material with a dielectric constant $K=5$.

Find:

The new capacitance.

Solution:

The capacitance of a parallel plate air capacitor is $C$.

The dielectric constant, $K=5$.

The capacitance formula is given by:

$C=\frac{\varepsilon _oA}{d}$, where $\varepsilon _o,A,d$ are the electrostatic constant, area, and distance between the plates respectively.

When the plate is divided into half.

The new capacitance,

$C'=\frac{(\frac{A}{2} )(5)\varepsilon _o}{d} +\frac{\frac{A}{2}\varepsilon _o }{d}$

$C'=3\frac{A\varepsilon _o}{d} \\C'=3C$

Therefore, the new capacitance is $3C$.

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