Question

14. A particle moves in a circle of radius 5 cm with
constant speed and time period 0.2 ms. The
acceleration of the particle is
[AIPMT (Prelims)-2011]
(1) 5 m/s2
(2) 15 m/s2
(3) 25 m/s2
(4) 36 m/s2​

Answer 1

Answer:

radius= 5cm= 0.05 m

Time period = 0.2π sec

Then,

Aceleration = v^2

r

Since, v= 2πr

t

v= 2π0.05

0.2π

v= 0.5m/s

So, a = 0.5×0.5

0.05

a= 5m/s^2