Physics, asked by rambaburoy733, 1 month ago

14. A particle starts from origin, goes along x-axis to the

point having coordinate (10 m, 0 m) and then

returns along the same line to the point having

coordinate (–5 m, 0), then distance travelled by

particle is

(1) 5 m (2) 10 m

(3) 20 m (4) 25 m​

Answers

Answered by hanshapahadi0182
0

Answer:

30 m, - 10 m

The distance and displacement of the particle during the trip are 30 m and -10 m.

Explanation:

Given that,

A particle start from the origin, goes along x-axis to the point (10m,0) and then returns along the same line to the point (-10m,0).

We need to draw the figure.

We calculate the distance

A particle moves 10 meter from the origin O to A along the x axis and then along the same line.

Now, a particle moves 10 m from A to O and 10 m O to B

The total distance is

d =10+10+10=30\ md=10+10+10=30 m

The displacement is the shortest distance between starting point and end point.

D = -10\ mD=−10 m

Hence, The distance and displacement of the particle during the trip are 30 m and -10 m.

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