Question

14. A piece of elastic was stretched by 24% to a
length of 31 cm. Find its unstretched original
length
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Answer 1

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Let the original length be x

$\sf \frac{24}{100}x = \frac{6}{25} x$

A.T.Q.

$\sf \: x + \frac{6}{25} x = 31$

$\sf \: \frac{(25x + 6x)}{25} = 31$

$\sf31x = 31 \times 25$

$\sf \: x = \frac{775}{31} = 25$

So the unstretched length is 25 cm

Hope it helps you.....