Question

14) A planet existed whose mass and radius both
were half those of the earth what will be the
acceleration due to growity cos at its surface​

Answer 1

Answer:

As we know that the acceleration in earth is calculated by the formula (Gm)/(r^2) which equals 9.8m/s^2 where m is the mass of the earth and r is the radius of the earth. so, the value of g on that planet will be 19.6m/s^2.