Question

14. A rectangle has same area as that of a square of side 10 m. If the breadth of the
rectangle is 8 m, find the perimeter of the rectangle. solve please​

Answer 1

Answer:

Step-by-step explanation:

Area of rectangle= area of square

Area of square= 100 cm² (side* side, i.e., 10*10)

Area of rectangle

length*8= 100

Length of rectangle= 100/8

= 12.5 cm

Now, perimeter= 2(12.5+8)

=2*20.5

= 41 cm.

Hope this helps you.

Wishing you a happy and prosperous new year too. :)

Answer 2

• Given

• Area of rectangle is same as the area of square
• Breadth of rectangle = 8 m

• To find

• Perimeter of rectangle

• Solution

Area of square = side × side

⇒ 10 × 10

⇒ 100 m²

• Area of square = 100 m²

Area of square = Area of rectangle

Area of rectangle = length × breadth

⇒ 100 = length × breadth

⇒ 100 = length × 8

⇒ 100/8 = length

⇒ 12.5 = length

• Length of rectangle = 12.5 m

Dimensions of rectangle -

• Length = 12.5 m
• Breadth = 8 m

Perimeter of rectangle = 2(length + breadth)

⇒ 2(12.5 + 8)

⇒ 2(20.5)

⇒ 41 m

• Perimeter of rectangle = 41 m

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Some related formulae -

• Diagonal of rectangle = $\sf{\sqrt{l^2 + b^2}}$
• Perimeter of square = 4 × side
• Diagonal of square = $\sf{\sqrt{2}a}$