14. A shopkeeper bought two chairs for 3120. He sold one of them at a gain of 36% but the other was sold for
a loss of 15%. He found that each chair was sold for the same price.
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Answer:
LET CP OF ONE CHAIR=a
i.e. CP OF OTHER CHAIR=3120-a....................1
i.e. SP OF FIRST CHAIR=(a)(136/100)=136a/100
AND SP OF SECOND CHAIR=(3120-a)(85/100)=(265200-85a)/100
i.e. 136a/100=(265200-85a)/100
i.e. 136a=265200-85a
i.e. 221a=265200
i.e. a=1200=CP OF FIRST CHAIR
AND CP OF SECOND CHAIR=3120-1200=1920
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