14....A space craft flying in a straight course with velocity of 75 km s fires its rocket motors for 6-0 s. At the end of this time, its speed is 120 km s- in the same direction. Find : (i) the space craft's average acceleration while the motors were firing, (ii) the distance travelled by the space craft in the first 10 s after the rocket motors were started, the motors having been in action for only
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Explanation:
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Answer:
Let take, u = 75km/s
v = 120km/s
and t = 6 sec
Now using the following relation, v = u + at
a = v - u / t
a = 120 - 75 / 6
a = 7.5km/s
Now using this equation, v^2 = u^2 + 2as
s = v^2 - u^2 / 2a
s = (120)^2 - (75)^2 / 2*7.5
s = 585km
assuming that after 6sec the rocket stops andbeing in space and due to inetria it continued to move at a constant velocity of 120km/s. Thus after 6sec the rocket travels for 4 more seconds, that distance is
= 120 * 4
= 480
The total distance travelled by rocket for 10 seconds = 585 + 480
= 1065km
Explanation: