Question

14. A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity
just before touching the ground. (g = 9.8 m/s) (a) 384.16 m/ s

(b) 196 m/s

(c) 19.6 m/s

(d) 3841.4 m/s​

Answer 1

Answer:

The answer is c

Explanation:

$v {}^{2} + u {}^{2} = 2as \\ v = \sqrt{2 \times 9.8 \times 19.6 } \\ v = \sqrt{ {2}^{2} \times {9.8}^{2} } \\ v = 19.6$

Answer 2

Answer:

c. 19.6 m/s

Explanation:

we know that;

                  v=$\sqrt{2gy$

v=$\sqrt{2*9.8*19.6$=19.6m/s