Question

14. A stone is released from the top of a tower of height 19.6 m. Calculate its
final velocity just before touching the ground.​

Answer 1

Answer:

v= 19.6m/s

Explanation:

u=0m/s

s=19.6m

a=9.8m/s^2

v^2=u^2+2as

v=19.6m/s

Answer 2

Answer:

19.6m/s

Explanation:

u=0,v=?,height=19.6m

$v { }^{2} = u { }^{2} + 2gs$

v2= 0+ 2 . 9.8×19.6

v2=384.16

v=19.6m/s