Question

14. A stone is released from the top of a tower of height 19.6 m
Calculate its final velocity just before touching the ground
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Answer 1

Answer:

intial velocity (u)=0

final velocity (v)=x

according to third equation of motion

v²=u²+2gh

=x²=2×9.8×19.6

x=√2×9.8×19.6

i.e x=19.6 m/s

here is your answer

Answer 2

Answer:

velocity just before touching the ground is 19.6 m/s

Explanation:

Height= 19.6m g=9.8m/s²

final velocity= v= √(2×g×h)

v= √(2×9.8×19.6)  m/s

v= √(384.16)  m/s

v=19.6 m/s