Question

14. A thin walled pipe purely rolls along the floor. Ratio of
its rotational kinetic energy to total kinetic energy is​

Answer 1

Answer:

Ratio of  its rotational kinetic energy to total kinetic energy is 1:1

Explanation:

According to the problem the pipe purely rolls along the floor.

Therefore the transitional kinetic energy of the pipe is 1/2 m v^2

where m is the mass of the pipe and v is velocity

and the rotational kinetic energy will be  1/2  m r^2 x (v/ r)^2

 therefore the ratio between them,  1/2 m v^2/ 1/2  m r^2 x (v/ r)^2

                                                           = 1

therefore the ratio is 1:1

Answer 2

Answer:

1:2

Explanation:

Please refer to the picture attached.

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